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FM/BG-622 · v1.02
Ballistic solution Example: Calculation
- Code
- FM/BG-622
- Kind
- Guide
- Version
- v1.02 2yrs ago
- Views
- 308
- Platforms
- As its document
- Published by
- MSG mbaker5114 16 Jun 2024
- Last material change
- v1.00
No words changed between v1.01 and v1.02.
v1.01
Preparation
Sgt McShooty is deployed as a Spotter (Manual) on a Honeybadger. He aims for to be able to assemble a ballistic solution in any conditions, so he prepares calculations for the operation.
His sniper is using the M24 SWS and they will only be using the M118 LR bullet. Prior to operation start, he looks at an ATragMX to record time of flight for his given atmospherics.
Target Range Time of Flight
400m 0.61s
500m 0.79s
600m 0.99s
700m 1.20s
800m 1.43s
900m 1.68s
1000m 1.95s
Target Requirements
In operation, Sgt McShooty identifies an OPFOR machine gunner engaging a friendly squad. A follow up shot will not compromise any objectives, so he can disregard most Tertiary Components entirely.
In addition to this, he is presented with fairly typical shot conditions, as:
There is no wind present
The target is stationary while firing
He is not firing at a steep incline
Category Ballistic Component Direction of Deflection
Primary Bullet Drop (composite) Vertical
Primary Moving Targets Horizontal
Primary Crosswinds Horizontal
Secondary Inclined Shooting Vertical
Secondary Spin Drift Horizontal
Secondary Coriolis Effect Horizontal
Tertiary Eotvös Effect Vertical
Tertiary Headwinds & Tailwinds Vertical
Tertiary Air Density changes Vertical
Ballistic Solution Assembly
Bullet Drop
Sgt McShooty ranges his target at 800m according to https://unitedtaskforce.net/handbook?c=marksmanship-temp&g=FMG83. Looking at his range card, he finds a bullet drop adjustment of 9.1 mils.
Spin Drift
He uses the Spin Drift formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/558/spin-drift-calculation:
((SG * Time of Flight ^ 1.83) / Distance) * 1000 = Spin Drift in MRADs
((.0759 * 1.43 ^ 1.83) / 800) * 1000 = .18 MRADs
Because his barrel twist is right hand, his bullet will deflect .18 MRADs to the right.
Coriolis Effect
He uses the Horizontal Coriolis Effect formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/553/horizontal-coriolis-force-calculation:
cos(latitude°) * (Time of flight in seconds) * .072 = Horizontal deflection in MRADs
cos(35°) * (1.43) * .072 = .08 MRADs to the Right
Final Ballistic Solution
Sgt McShooty adds his two horizontal components together for a total of .26 MRADs to the right.
Because his deflection is low and to the left, he tells his sniper to adjust up and to the right
Final Ballistic Solution: 9.1 mils up, 0.26 mils left
v1.02
Preparation
Sgt McShooty is deployed as a Spotter (Manual) on a Honeybadger. He aims for to be able to assemble a ballistic solution in any conditions, so he prepares calculations for the operation.
His sniper is using the M24 SWS and they will only be using the M118 LR bullet. Prior to operation start, he looks at an ATragMX to record time of flight for his given atmospherics.
Target Range Time of Flight
400m 0.61s
500m 0.79s
600m 0.99s
700m 1.20s
800m 1.43s
900m 1.68s
1000m 1.95s
Target Requirements
In operation, Sgt McShooty identifies an OPFOR machine gunner engaging a friendly squad. A follow up shot will not compromise any objectives, so he can disregard most Tertiary Components entirely.
In addition to this, he is presented with fairly typical shot conditions, as:
There is no wind present
The target is stationary while firing
He is not firing at a steep incline
Category Ballistic Component Direction of Deflection
Primary Bullet Drop (composite) Vertical
Primary Moving Targets Horizontal
Primary Crosswinds Horizontal
Secondary Inclined Shooting Vertical
Secondary Spin Drift Horizontal
Secondary Coriolis Effect Horizontal
Tertiary Eotvös Effect Vertical
Tertiary Headwinds & Tailwinds Vertical
Tertiary Air Density changes Vertical
Ballistic Solution Assembly
Bullet Drop
Sgt McShooty ranges his target at 800m according to https://unitedtaskforce.net/handbook?c=marksmanship-temp&g=FMG83. Looking at his range card, he finds a bullet drop adjustment of 9.1 mils.
Spin Drift
He uses the Spin Drift formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/558/spin-drift-calculation:
((SG * Time of Flight ^ 1.83) / Distance) * 1000 = Spin Drift in MRADs
((.0759 * 1.43 ^ 1.83) / 800) * 1000 = .18 MRADs
Because his barrel twist is right hand, his bullet will deflect .18 MRADs to the right.
Coriolis Effect
He uses the Horizontal Coriolis Effect formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/553/horizontal-coriolis-force-calculation:
cos(latitude°) * (Time of flight in seconds) * .072 = Horizontal deflection in MRADs
cos(35°) * (1.43) * .072 = .08 MRADs to the Right
Final Ballistic Solution
Sgt McShooty adds his two horizontal components together for a total of .26 MRADs to the right.
Because his deflection is low and to the left, he tells his sniper to adjust up and to the right
Final Ballistic Solution: 9.1 mils up, 0.26 mils left
Preparation
Sgt McShooty is deployed as a Spotter (Manual) on a Honeybadger. He aims for to be able to assemble a ballistic solution in any conditions, so he prepares calculations for the operation.
His sniper is using the M24 SWS and they will only be using the M118 LR bullet. Prior to operation start, he looks at an ATragMX to record time of flight for his given atmospherics.
Target Range Time of Flight
400m 0.61s
500m 0.79s
600m 0.99s
700m 1.20s
800m 1.43s
900m 1.68s
1000m 1.95s
Target Requirements
In operation, Sgt McShooty identifies an OPFOR machine gunner engaging a friendly squad. A follow up shot will not compromise any objectives, so he can disregard most Tertiary Components entirely.
In addition to this, he is presented with fairly typical shot conditions, as:
There is no wind present
The target is stationary while firing
He is not firing at a steep incline
Category Ballistic Component Direction of Deflection
Primary Bullet Drop (composite) Vertical
Primary Moving Targets Horizontal
Primary Crosswinds Horizontal
Secondary Inclined Shooting Vertical
Secondary Spin Drift Horizontal
Secondary Coriolis Effect Horizontal
Tertiary Eotvös Effect Vertical
Tertiary Headwinds & Tailwinds Vertical
Tertiary Air Density changes Vertical
Ballistic Solution Assembly
Bullet Drop
Sgt McShooty ranges his target at 800m according to https://unitedtaskforce.net/handbook?c=marksmanship-temp&g=FMG83. Looking at his range card, he finds a bullet drop adjustment of 9.1 mils.
Spin Drift
He uses the Spin Drift formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/558/spin-drift-calculation:
((SG * Time of Flight ^ 1.83) / Distance) * 1000 = Spin Drift in MRADs
((.0759 * 1.43 ^ 1.83) / 800) * 1000 = .18 MRADs
Because his barrel twist is right hand, his bullet will deflect .18 MRADs to the right.
Coriolis Effect
He uses the Horizontal Coriolis Effect formula to calculate horizontal deflection according to https://unitedtaskforce.net/handbook/block/553/horizontal-coriolis-force-calculation:
cos(latitude°) * (Time of flight in seconds) * .072 = Horizontal deflection in MRADs
cos(35°) * (1.43) * .072 = .08 MRADs to the Right
Final Ballistic Solution
Sgt McShooty adds his two horizontal components together for a total of .26 MRADs to the right.
Because his deflection is low and to the left, he tells his sniper to adjust up and to the right
Final Ballistic Solution: 9.1 mils up, 0.26 mils left
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FM/G80 Manual ballisticsOn role cards
On 2 role cards in 1 combat area.
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Marksmanship
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