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Force Manual

The FM outlines our core skills, policies and guides to ensure every member stands ready for the mission ahead.

FM/BG-622 · v1.10

Ballistic solution example: calculation

Code
FM/BG-622
Kind
Guide
Version
v1.10 2yrs ago
Views
308
Platforms
As its document
Published by
SP3 Jochem 5 Jul 2024
Last material change
v1.00

8 words added, 8 words removed. Title changed from "Ballistic solution Example: Calculation" to "Ballistic solution example: calculation".

Preparation Sgt McShooty is deployed as a Spotter (Manual) on a Honeybadger. He aims for to be able to assemble a ballistic solution in any conditions, so he prepares calculations for the operation. His sniper is using the M24 SWS and they will only be using the M118 LR bullet. Prior to operation start, he looks at an ATragMX to record time of flight for his given atmospherics. Target Range Time of Flight 400m 0.61s 500m 0.79s 600m 0.99s 700m 1.20s 800m 1.43s 900m 1.68s 1000m 1.95s Target Requirements requirements In operation, Sgt McShooty identifies an OPFOR machine gunner engaging a friendly squad. A follow up shot will not compromise any objectives, so he can disregard most Tertiary Components entirely. In addition to this, he is presented with fairly typical shot conditions, as: There is no wind present The target is stationary He is not firing at a steep incline Category Ballistic Component Direction of Deflection Primary Bullet Drop (composite) Vertical Primary Moving Targets Horizontal Primary Crosswinds Horizontal Secondary Inclined Shooting Vertical Secondary Spin Drift Horizontal Secondary Coriolis Effect Horizontal Tertiary Eotvös Effect Vertical Tertiary Headwinds & Tailwinds Vertical Tertiary Air Density changes Vertical Ballistic Solution Assembly solution assembly Bullet Drop drop Sgt McShooty ranges his target at 800m according to [[522]]. Looking at his range card, he finds a bullet drop adjustment of 9.1 mils. Spin Drift drift He uses the Spin Drift formula to calculate horizontal deflection according to [[558]]: ((SG * Time of Flight ^ 1.83) / Distance) * 1000 = Spin Drift in MRADs ((.0759 * 1.43 ^ 1.83) / 800) * 1000 = .18 MRADs Because his barrel twist is right hand, his bullet will deflect .18 MRADs to the right. Coriolis Effect effect He uses the Horizontal Coriolis Effect formula to calculate horizontal deflection according to [[553]]: cos(latitude°) * (Time of flight in seconds) * .072 = Horizontal deflection in MRADs cos(35°) * (1.43) * .072 = .08 MRADs to the Right Final Ballistic Solution ballistic solution Sgt McShooty adds his two horizontal components together for a total of .26 MRADs to the right. Because his deflection is low and to the left, he tells his sniper to adjust up and to the right Final Ballistic Solution: 9.1 mils up, 0.26 mils left

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